如何通过php变量将html传递给jquery

Question

I'm just taking my first steps with js/jquery, and I was trying to reload the content of a table using jquery but I'm not figuring out how:

if(isset($_POST['mode']) && $_POST['mode'] == "toggleactive"){

    $admin = new funcadmin($dbo);

    if($admin->toggleState($_POST['id_users'])){

        $table = $admin->getUsers();
        echo json_encode($table); //??????
    }
    else{
        $erroruser = 'Erro!';
        echo json_encode($erroruser);
    }
}

and on the view:

<table id="userlist">    
<?php echo $table; ?> //How I load the original table

</table>
<script>
    function toggleState(id_users){
        $.ajax({
            type: "POST",
            url: "admin.php",
            data: {id_users:id_users, mode:"toggleactive"},
            dataType: "JSON",
            success: function(table) {
             $("#userlist").innerhtml('table');
            },
            error: function(err) {
            alert(err);
            }
        });
    }</script>

Many thanks in advance, Cheers, Baya

Answer 1

The problem had nothing to do with JQuery properly. The problem was here: if($admin->toggleState($_POST['id_users']))

I never told the function to return true, was kind of expecting that the return of the ->execute() to be enough. Now that I did its all working well.

My sincere applologies for your lost time, and thank you all for all the help you were willing to give.

Cheers, Baya