从弹出窗口释放Segue

Question

I have UIViewController A, UIVC B, and A has a segue to B. (Using a button) B has an "OK" button that pops up a window, and once I click "Accept" in the pop up, I want it to return back to UIVC A, or back to be upon "Cancel". Now, the cancel part is easy. How do I implement the returning back to A?

Answer 1

In viewcontroller A:

@IBAction func unwindToViewControllerA(segue:UIStoryboardSegue) { }

In ViewController B:

@IBAction func dismissClicked(_ sender: Any) {
     performSegue(withIdentifier: "unwindToViewControllerA", sender: self)
}

Make sure you create a named Segue called: unwindToViewControllerA , this I does by control - clicking to the EXIT icon (rather than the next view controller when you create a normal segue)

Answer 2

This link has a full, awesome explanation about how it needs to be done.

https://www.andrewcbancroft.com/2015/12/18/working-with-unwind-segues-programmatically-in-swift/