如何从另一个表单通用地打开一个表单？

Question

I have a total of 6 forms. In my mainForm, I have 5 buttons to open the other forms inside the panel. what i know is something like this:

 form1 f1 = new form1();
 f1.TopLevel = false;
 f1.Dock = DockStyle.Fill;
 this.panelMid.Controls.Add(f1);
 f1.show();

now, since I have 5 other forms, I want to make a function that would make me open the forms without re-typing those code in every button event. My problem is that I don't know to pass the form into a function as parameter.

Answer 1

DRY 101, based on your code, with some generics chucked in

public void MyAwesomeFormShower<TForm>()
   where TForm : Form, new()
{
   var form = new TForm();
   // common code here
   form.TopLevel = false;
   form.Dock = DockStyle.Fill;
   ///this.panelMid.Controls.Add(f1); // < who knows what this does, however don't do it
   form.Show();
}

Usage

MyAwesomeFormShower<MyLovelyHorseForm>();

---

Or if you want to get fancy

public void MyAwesomeFormShower<TForm>(Action<TForm> action = null) 
   where TForm : Form, new()   
{
   var form = new TForm();
   // common code here
   form.TopLevel = false;
   form.Dock = DockStyle.Fill;

   action?.Invoke();
   form.Show();
}

Usage

MyAwesomeFormShower<MyLovelyHorseForm>();

// or

MyAwesomeFormShower<MyLovelyHorseForm>((form) => 
     {   
         // Specialised form stuff here
         // that is specific to MyLovelyHorseForm
     });