正则表达式使用Java在第一个斜杠后获取所有字符

Question

I am trying to get all the characters after first slash.
I have tried the following but its not working
Can anyone share any sample regex to get all characters after first slash

String pattern = "[A-Za-z\\s]|(?<=[A-Za-z\\s])/";  

sample input - xx/abs-12345/67890
expected output - abs-12345/67890

Answer 1

This is the regex you need:

(?<=/).+

The lookbehind looks for a / and then matches every non-line-ending after it. Since the regex engine checks from left to right, it will always find the first slash.

    Matcher m = Pattern.compile("(?<=/).+").matcher("xx/abs-12345/67890");
    if (m.find()) {
        System.out.println(m.group());
    }

You can even do this in one line, without regex.

System.out.println(Arrays.stream(s.split("/")).skip(1).collect(Collectors.joining("/")));

s is the input string.

Answer 2

I think you don't need a regex to do that job. You can do like below.

String s = "123/abc23r";
String strAfterFirstSlash = s.substring(s.indexOf('/')+1,s.length());
char[] charsAfterFirstSlash = strAfterFirstSlash.toCharArray(); // If you need to get result in a char array
System.out.println(strAfterFirstSlash);

Output:

abc23r