(char*) 在 c 中是什么意思？

Question

What does char*ptr=(char*)&i; exactly do in the following code

#include <stdio.h>
 int main()
 {
  int i=32;
  char*ptr=(char*)&i;
  printf("%d",*ptr);
  return 0;
 }

Answer 1

char* ptr=(char*)&i;

i is of type int . So you are trying to cast address of i as a character pointer and assign it to a local variable called ptr . This way each byte stored in i can be read. Read more on pointers to understand in detail.