[英]sanic - How to specify required JSON?
I would like to specify the required JSON for a controller get
/ post
methods in order for it to show in SwaggerUI. 我想为控制器的get
/ post
方法指定所需的JSON,以便使其在SwaggerUI中显示。
For example, I want request.json
to look like this: 例如,我希望request.json
看起来像这样:
{
'key1': <int>,
'key2': <string>
}
I initialize SwaggerUI like this: 我这样初始化SwaggerUI:
from sanic_openapi import swagger_blueprint, openapi_blueprint
app = Sanic(__name__)
# Set up SwaggerUI
app.blueprint(openapi_blueprint)
app.blueprint(swagger_blueprint)
How can I make both keys show up in parameters
? 如何使两个键都显示在parameters
?
There is sanic_openapi.doc.consumes
decorator for decorating view functions to document their input. 有sanic_openapi.doc.consumes
装饰器,用于装饰视图函数以记录其输入。 This naming of the decorator function follows from the OpenAPI specification . 装饰器函数的命名遵循OpenAPI规范 。
Here is one way to apply it: 这是一种应用方法:
@app.post('/recording_test')
@doc.summary('Tests a recording')
@doc.consumes({'key1': str, 'key2': int}, location='body')
async def create_recording_test(request):
...
You can model your input using a class. 您可以使用类对输入进行建模。
class RecordingTest:
key1 = str
key2 = int
Use the modeled input above in the following manner 通过以下方式使用上面的建模输入
@app.post('/recording_test')
@doc.summary('Tests a recording')
@doc.consumes(RecordingTest, location='body')
async def create_recording_test(request):
...
You did not see this params in swagger because your get method is on class. 由于您的get方法位于类中,因此您不会大张旗鼓地看到这些参数。 Sanic-openapi and Sanic-swagger does not support class based views yet. Sanic-openapi和Sanic-swagger还不支持基于类的视图。 :( :(
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