[英]python, list with tuples, find consecutive numbers
The title is kind of misleading, but I can't really describe it in one line. 标题有点令人误解,但我无法真正描述它。
I have a list that looks like this. 我有一个看起来像这样的清单。
a = [(4, 2), (4, 3), (2, 1), (1, 0), (1, 4)]
The list was already sorted by the first term of the tuple, using this code. 使用此代码,该列表已按元组的第一项排序。
a.sort( key = lambda x: x[0], reverse = True )
(I am just saying that the list is already sorted, so there's no need to sort) (我只是说列表已经排序,因此无需排序)
Assume that the first term of the tuple is the score of a Poker player, and second term is the name of each Poker player. 假定元组的第一项是扑克玩家的分数,第二项是每个扑克玩家的名字。 So, the list above is the same as this:
因此,上面的列表与此相同:
[ ( score = 4, player 2 ), ( score = 4, player 3 ), (score = 2, player 1 ), (score = 1, player 0), (score = 1, player = 4) ] [(分数= 4,玩家2),(分数= 4,玩家3),(分数= 2,玩家1),(分数= 1,玩家0),(分数= 1,玩家= 4)]
There are 5 players, and the score of each players could be the same, or different. 有5个玩家,每个玩家的得分可以相同或不同。
I want to evaluate the players based on their score, and want to print result in case of ties (when . So, 我想根据他们的得分来评估球员,并希望在出现平局的情况下打印结果(因此,
Player 2 ties
Player 3 ties
Player 0 ties
Player 4 ties
Player 2 and 3 had the same score (score = 4) and they tied. 玩家2和3得分相同(得分= 4),并列并列。 Also, Player 0 and 4 ties, but since their score ( score = 1) was lower than that of Player 2 and 3, they were printed below player 2 and 3.
同样,玩家0和4并列,但由于他们的得分(得分= 1)低于玩家2和3,因此它们被打印在玩家2和3下方。
How can I do this in Python? 如何在Python中执行此操作?
This is a problem tailor-made for itertools.groupby
: 这是为
itertools.groupby
量身定制的问题:
>>> from itertools import groupby
>>> from operator import itemgetter
>>> L = [(4, 2), (4, 3), (2, 1), (1, 0), (1, 4)]
>>> for key, group in groupby(L, itemgetter(0)):
... group = list(group)
... if len(group) > 1:
... for k, player in group:
... assert k == key
... print(f'Player {player} ties')
... print()
...
Player 2 ties
Player 3 ties
Player 0 ties
Player 4 ties
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