[英]OR WHERE IN in laravel Query Builder with sub query
How can make query builder for following Query如何为以下查询制作查询构建器
SELECT * FROM `rad_nas` WHERE nas_assigned = ".$id."
OR nas_assigned IN
(select franchise_id from rad_franchise_has_parent where parent_id=".$id." )
OR nas_id IN
(select fra_nas_id from rad_franchise_has_nas where franchise_nas_id=".$id.")
Check the docs for future uses and don't post a question and expect other people to write or debug your code for you, that is your job, we are giving you guidance, but here is a complete example when you transform that to Query Builder
检查文档以供将来使用,不要发布问题并期望其他人为您编写或调试您的代码,这是您的工作,我们正在为您提供指导,但这里有一个完整的示例,当您将其转换为
Query Builder
$results = DB::table('rad_nas')->where('nas_assigned', $id)
->orWhereIn('nas_assigned', function($query) use ($id) {
$query->select('franchise_id')
->from('rad_franchise_has_parent')
->where('parent_id', $id);
}
->orWhereIn('nas_id', function($query) use ($id) {
$query->select('fra_nas_id')
->from('rad_franchise_has_nas')
->where('franchise_nas_id', $id);
}
As @DanielO pointed out正如@DanielO 指出的那样
Raw statements will be injected into the query as strings, so you should be extremely careful to not create SQL injection vulnerabilities.
原始语句将作为字符串注入到查询中,因此您应该非常小心,不要创建 SQL 注入漏洞。
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