printf上的clock_t输出值错误

Question

I have the following code:

#include <stdio.h>
#include <time.h>

clock_t a;

void f(void) {
    a = clock();
    printf("in f(): %g\n", a);
}

void main(void) {
    f();
    printf("in main(): %g\n", a);
}

Compiling it with MinGW gcc and running it produces output similar to this:

in f(): -1.#QNAN
in main(): 1.49845e-307

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Question : Why does a contain -1.#QNAN ? While I understand what it means , I do not see what went wrong in the code. At first, I speculated that it has something to do with the printing format specifier for type clock_t , but answers from this stackoverflow thread says otherwise. Even to make sure, I did a quick digging in the standard headers and found out that clock_t is a typedef for long (at least on my machine), which means that there is nothing wrong with regards to displaying the value. Could it be a bug in the clock() function?

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Edit : Just after reading the comments, I realized that my actual problem is that I was expecting a to be some super small floating-point value so badly that I forgot clock_t is, as I said, defined on my machine as of type long . Sorry for the bother and thank you all for your time.

Answer 1

Please always take a look at your compiler warning:

warning: format specifies type 'double' but the argument has type
      'clock_t' (aka 'unsigned long') [-Wformat]
    printf("in f(): %g\n", a);
                    ~~     ^
                    %lu

Compiler even tells you how to fix. In short, you can't specify a double to printf() when the data is unsigned long .

Answer 2

%g is for printing floating point numbers, but you passed a clock_t (which can be any arithmetic type; such as a 32 bit integer).

You need to cast to a double if you want to use %g :

printf("in main(): %g\n", static_cast<double>(a));