[英]SQL number greater than select results
I'm struggling to think of a way to do this with T-SQL. 我正在努力想办法用T-SQL做到这一点。
I have a table which is populated every 5 seconds with the prices of three currencies (GBP, EUR & USD) 我有一个表格,该表格每5秒填充三种货币(GBP,EUR和USD)的价格
I've created a trigger (after insert), which selects the last 5 records entered for a given currency: 我创建了一个触发器(插入后),该触发器选择为给定货币输入的最后5条记录:
SELECT TOP 5 Price from dbo.prices where coin='GBP' ORDER BY Date Desc
I want to determine if the last inserted currency price is greater than the selected 5 above, how do i do this? 我想确定最后插入的货币价格是否大于上面选择的5,我该怎么做?
Thanks 谢谢
As I guess: there cant be two entries for the same currency at one time. 我猜想:一次不能有两个输入相同货币的条目。 Only one insert per currency per some time (5sec).
每一段时间(5秒)每种货币只能插入一次。 So this should fit yours requirements:
因此,这应该符合您的要求:
declare @prices table ([Date] int IDENTITY(1,1) primary key, Price float, coin varchar(3));
insert into @prices (coin, Price) values
('GBP', 3.20),('EUR', 3.14),('USD', 3.14),
('GBP', 3.17),('EUR', 3.16),('USD', 3.11),
('GBP', 3.14),('EUR', 3.13),('USD', 3.16),
('GBP', 3.15),('EUR', 3.12),('USD', 3.17),
('GBP', 3.16),('EUR', 3.17),('USD', 3.11),
('GBP', 3.15),('EUR', 3.14),('USD', 3.12),
('GBP', 3.19),('EUR', 3.14),('USD', 3.16)
select
case
when NEW.Price > PREV.Price Then 'yes'
else 'No'
end as CURR_JUMP_UP
from
(
select top 1 COALESCE(Price,0) Price, [Date]
from @prices where coin='GBP' order by [Date] desc
) NEW
cross apply
(
select MAX(Price) Price from
(
select top 5 Price
from @prices
where coin='GBP' and [Date]<NEW.[Date]
order by [Date] desc
) t
) PREV
Try this query: 试试这个查询:
DECLARE @AmountLastFiveEntry DECIMAL= (SELECT TOP 5 SUM(Price) FROM dbo.prices WHERE
ID NOT IN (SELECT TOP 1 ID
FROM dbo.prices where coin='GBP' ORDER BY Date Desc) where coin='GBP' ORDER BY Date Desc)
IF @AmountLastFiveEntry<(SELECT TOP 1 Price
FROM dbo.prices where coin='GBP' ORDER BY Date Desc)
BEGIN
SELECT @AmountLastFiveEntry --To do task
END
Trigger part is confusing 触发部分令人困惑
This will report if the latest price is higher (or equal) to the largest of the prior 5. 这将报告最新价格是否高于(或等于)先前5个的最高价格。
declare @currency table (iden int IDENTITY(1,1) primary key, exchange smallint, coin tinyint);
insert into @currency (coin, exchange) values
(1, 1)
, (1, 2)
, (1, 3)
, (1, 4)
, (1, 5)
, (1, 6)
, (2, 1)
, (2, 2)
, (2, 3)
, (2, 4)
, (2, 5)
, (2, 3);
select cccc.coin, cccc.exchange
, case when cccc.rn = cccc.rne then 'yes'
else 'no'
end as 'high'
from ( select ccc.iden, ccc.coin, ccc.exchange, ccc.rn
, ROW_NUMBER() over (partition by ccc.coin order by ccc.exchange desc, ccc.rn) rne
from ( select cc.iden, cc.coin, cc.exchange, cc.rn
from ( select c.iden, c.coin, c.exchange
, ROW_NUMBER() over (partition by coin order by iden desc) as rn
from @currency c
) cc
where cc.rn <= 6
) ccc
) cccc
where cccc.rn = 1
order by cccc.coin
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