[英]Drop string that is all zeros - pandas python
I have a dataframe of strings that looks like this: 我有一个像这样的字符串数据框:
In [58]: d['upin'].head()
Out[58]:
0 'H8409
1 'H8409
2 .31961
3 .31961
4 000000
Name: upin, dtype: object
I want to drop the rows that have only zeros, ie the last row in this example. 我想删除只有零的行,即本示例中的最后一行。 I haven't found a nice regexp way of doing this, and I'm not sure what else to try. 我还没有找到一个很好的正则表达式来做到这一点,而且我不确定还有什么尝试。
This should work if I understood your problem correctly: 如果我正确理解了您的问题,这应该可以工作:
df = pd.DataFrame()
df['pin'] = ["00000","F4923","'222R","0","00001"]
ndf = df[~(df['pin'].str.contains('^0+$'))]
You can use pd.to_numeric: 您可以使用pd.to_numeric:
df.loc[pd.to_numeric(df.pin,errors='coerce').ne(0)]
Out[278]:
pin
1 F4923
2 '222R
4 00001
You can use str.contains 您可以使用str.contains
df = df[df.upin.str.contains('[^0]')]
You get 你得到
upin
0 'H8409
1 'H8409
2 .31961
3 .31961
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.