Oracle DB 查询以获取记录计数并随后计算平均值

Question

Could anyone please help me regarding that Oracle query. Here is my required output. Thanks in advanced.from below query return some record i want to Calculate Average means SUM(COST+DURATION)/No.of row return form that query but below query doing partition based on SITE_ID i dont want any partition,What is want is whatever query return (Sum of all Duration+sum of all Cost/No. of row returns)but without any partition is that any way i can do that

select * from ( SELECT ROW_NUMBER() OVER (ORDER BY 1) RN,
SITE_ID,
CASEID, WOID, DURATION,
COST,
(SUM(COST+DURATION) OVER(PARTITION BY SITE_ID))/COUNT as TotalCost from

     (
      SELECT  COUNT(*) OVER () as COUNT,
      SITE_ID,  
      CASEID,
      WOID,
      ROUND(table1.duration/3600,2) AS DURATION,
      ROUND(table2.duration/3600),2) AS COST
       FROM table1  ) AVG

WHERE (1=1) ) where rn between 0 and 1000

Answer 1

On the basis of your revised question what I think you want is the total of COST and DURATION for each SITE, plus an average of these figures derived from the number of entries in table1 and table2 . This is what this query does:

select site_id
       , duration
       , cost
       , (duration+cost)/no_of as avg_total_cost
from (
    select
      table1.site_id
      , count(*) as no_of
      , sum(round(table1.duration/3600,2)) as duration
      , sum(round((table1.labor_rate * table2.duration)/3600,2)) as cost
    from table1
    inner join table2
        on table1.id = table2.id
    group by table1.site_id 
)
/

Here is a SQL Fiddle demo to prove that this query runs successfully.

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Your question appears to reference other tables, site and emp , which I have ignored because you don't provide join conditions for them. Likewise I have ignored the top-n filter; you can add it back it if you want.