检查一个字符串在另一个字符串中出现的次数

Question

Currently, I have a code that tells me if a string is in another string. However, I do not want it to stop the moment it finds the string. Instead, I want it to continue and tell me the total number of time it duplicates. Eg. "110010","10" Expected answer: 2 Given answer: 1

Below is my code.

def occurence(s1,s2):
    count == 0
    if s2 in s1:
        count += 1
        return count

Answer 1

You can just use the func count .

In your case, use : s1.count(s2)

Answer 2

You could just loop through the s1 with slices of size of the s2 and count if the slice is equal to s2

s1 = '110010'
s2 = '10'
count = 0
for i in range(0,len(s1)-len(s2)+1):
    if s1[i:i+len(s2)] == s2:
        count += 1

print(count)

which outputs: 2