ZeroDivisionError：整数除法或模数为零

Question

I am building a simple algorithm to find common divisors between two given numbers:

i = int(input("digite o 1o inteiro positivo: "))
j = int(input("digite o 2o inteiro positivo: "))

#i,j = 9,6 
aux, cont = 1, 0 

if i > j: # 9 < 6 
    for n in range (i+1): # n = (1,2,3,4,5,6,7,8,9) 
        while n <= i: # (1,2,3,4,5,6,7,8,9) 
            if i % n == 0 and j % n == 0: # 9 % (1,3,9) e 6 % (1,3,6) 
                print(n) # print(1,3)

Why is my programm having this ZeroDivisionError ?

Answer 1

Start your range() at 1, not 0 with:

Code:

for n in range(1, i + 1):  # n = (1,2,3,4,5,6,7,8,9)

Test Code:

i, j = 9, 6
if i > j:  # 9 < 6
    for n in range(1, i + 1):  # n = (1,2,3,4,5,6,7,8,9)
        if i % n == 0 and j % n == 0:  # 9 % (1,3,9) e 6 % (1,3,6)
            print(n)  # print(1,3)

Results:

1
3

Answer 2

I actually just wanted to indent the code in your question, but I ended up accidentally repairing it. So, here is a working solution:

i = int(input("Give the first positive integer: "))
j = int(input("Give the second positive integer: "))

r = j
if i < j:
  r = i

for n in range (2, r + 1):
  if i % n == 0 and j % n == 0:
    print(n)

Output:

Give the first positive integer: 27
Give the second positive integer: 18
3
9

The range starts with 2 , because 1 is a unit, and therefore not interesting as divisor (it divides everything anyway). The 0 should not be checked, because it does not divide anything, and because it caused Div-by-zero errors.

Whatever... Refreshed some python...

Answer 3

Your loop starts with 0 so this ZeroDivisionError occurs.

exception ZeroDivisionError Raised when the second argument of a division or modulo operation is zero. The associated value is a string indicating the type of the operands and the operation. [source]

You have to start your for loop from 1

like this: for n in range(1,i+1):

and you don't have to do while loop this will go infinite.

your code will be:

i = int(input("digite o 1o inteiro positivo: "))
j = int(input("digite o 2o inteiro positivo: "))

# i,j = 9,6 
aux, cont = 1, 0 

if i > j: # 9 < 6
    for n in range (1,i+1): # n = (1,2,3,4,5,6,7,8,9)
        #while n <= i: # (1,2,3,4,5,6,7,8,9)
        if i % n == 0 and j % n == 0: # 9 % (1,3,9) e 6 % (1,3,6)
            print(n) # print(1,3)

or you can also write your code in try-except block, like this which will give the same output:

i = int(input("digite o 1o inteiro positivo: "))
j = int(input("digite o 2o inteiro positivo: "))

# i,j = 9,6 
aux, cont = 1, 0 

if i > j: # 9 < 6
    for n in range (i+1): # n = (1,2,3,4,5,6,7,8,9)
        try:
          if i % n == 0 and j % n == 0: # 9 % (1,3,9) e 6 % (1,3,6)
              print(n) # print(1,3)
        except ZeroDivisionError:
            n+= 1

output

digite o 1o inteiro positivo: 9
digite o 2o inteiro positivo: 6

1
3

Answer 4

Function range() can have up to 3 arguments:

range(initial limit included, final limit not included, step)

• If you use for x in range(y) with only one argument, and such case is equal to: for y in range(0, x, 1) # including: [0, 1, ..., x - 1]

• If you need to start your range with 1, you need to define it: for y in range(1, y)

• If you need to change range step, you also need to define it: for y in range(0, -50, -1)