在Counter，Python中添加0计数值

Question

I have written a snippet that fetches ( dates )data from database and counts the occurrences of dates accordingly. However since the data in the Db is not consistent some of the dates are not present.My code is Below:

import MySQLdb
import sys
import matplotlib.pyplot as plt
from collections import Counter, OrderedDict

connection = MySQLdb.connect ()

cursor = connection.cursor ()

cursor.execute ()

#fetch all of the rows from the query
data = cursor.fetchall()
ddt =  sorted(set(data))

coll = Counter(data)
orddict = OrderedDict(sorted(coll.items()))# Sorts the dates in order
print orddict 

The output is here:

Is there a way where I can get(print) the missing dates in between with count 0?

Edit 1 : I tried printing out a datelist in sequence however ,the code only prints today's date.The code is as follows:

def dert():
    d1 = date(2017, 07, 15)  # start date
    d2 = datetime.date.today()  # end date
    delta = d2 - d1         # timedelta 
    for i in range(delta.days + 1):
        x = (d1 + timedelta(days= i))
    return  x 
print dert()

Answer 1

It seems to me that you could create an additional list which will contain all dates in sequential order starting from the needed date/first date in db.

Now once you have the additional list you can run on the in checking for each if it is in the db, if in db print count, otherwise print 0