查找字符串列表中的至少一个字符串是否没有字符（python）

Question

I want to check if, among the elements of a list of strings, at least one of the element has not a "-" in it. I tried :

print not any("-" in elem for elem in my_list)

With:

my_list = ['gta', '---', '---', 'gta']

it should return True and with :

my_list = ['gt-', 'ac-', 'ca-', 'gt-']

It should return False . It's always False for now, is there a one-line command to do that ? I could choose the easy way and make my code on several lines, but I want to practice these kinds of commands :).

Answer 1

如评论中所述，由于not any变成all not您不需要使用not all 。

Answer 2

You can use re.findall to check if the entire string in the list is composed of "-" :

import re
def check_string(s):
   return any(re.findall('^-+$', i) for i in s)

lists = [[['gta', '---', '---', 'gta'], True], [['gt-', 'ac-', 'ca-', 'gt-'], False]]
for a, b in lists:
   assert check_string(a) == b