[英]Different outputs using switch and if else statements in JavaScript
I am a beginner in learning programming, more specifically JavaScript. 我是学习编程(特别是JavaScript)的初学者。 I have come across a small problem while studying coding.
我在学习编码时遇到了一个小问题。 When I use switch statements to solve a piece of problem, it produces right output.
当我使用switch语句解决一个问题时,它会产生正确的输出。
var dateNow = 3; var dateSuffix; switch (dateNow) { case 1: case 21: case 31: dateSuffix = "st"; break; case 2: case 22: dateSuffix = "nd"; break; case 3: case 23: dateSuffix = "rd"; break; default: dateSuffix = "th"; break; } console.log("Today is the " + dateNow + dateSuffix + " day.");
But when I do the same with if else statements, the output is wrong. 但是当我对if else语句执行相同操作时,输出错误。
var dateNow = 3; var dateSuffix; if (dateNow == 1 || 21 || 31) { dateSuffix = "st"; } else if (dateNow == 2 || 22) { dateSuffix = "nd"; } else if (dateNow == 3 || 23) { dateSuffix = "rd"; } else { dateSuffix = "th"; } console.log("Today is " + dateNow + dateSuffix + " day of the month...");
Could anyone please point out the problem with my if statements? 任何人都可以指出我的if语句存在的问题吗?
You can't use dateNow == 1 || 21 || 31
您不能使用
dateNow == 1 || 21 || 31
dateNow == 1 || 21 || 31
dateNow == 1 || 21 || 31
. dateNow == 1 || 21 || 31
。
You need to use either [1,21,31].includes(dateNow)
您需要使用
[1,21,31].includes(dateNow)
Or dateNow == 1 || dateNow == 21 || dateNow == 31
或
dateNow == 1 || dateNow == 21 || dateNow == 31
dateNow == 1 || dateNow == 21 || dateNow == 31
var dateNow = 3; var dateSuffix; if ([1,21,31].includes(dateNow)) { dateSuffix = "st"; } else if ([2,22].includes(dateNow)) { dateSuffix = "nd"; } else if ([3,23].includes(dateNow)) { dateSuffix = "rd"; } else { dateSuffix = "th"; } console.log("Today is " + dateNow + dateSuffix + " day of the month...");
var dateNow = 3; var dateSuffix; if (dateNow == 1 || dateNow ==21 || dateNow ==31) { dateSuffix = "st"; } else if (dateNow == 2 || dateNow ==22) { dateSuffix = "nd"; } else if (dateNow == 3 || dateNow ==23) { dateSuffix = "rd"; } else { dateSuffix = "th"; } console.log("Today is " + dateNow + dateSuffix + " day of the month...");
if (dateNow == 1 || 21 || 31) {
with is code if (dateNow == 1 || dateNow ==21 || dateNow ==31) {
your code only trigger first if condition This code will help you with是代码
if (dateNow == 1 || dateNow ==21 || dateNow ==31) {
您的代码仅在条件满足时才触发
Update: As @Xufox pointed out, this answer is not true. 更新:如@Xufox所指出,此答案不正确。 This is false.
这是错误的。
In addition to @Zenoo's answer, I have tested with this code: 除了@Zenoo的答案,我还使用以下代码进行了测试:
dateNow = 2
console.log(dateNow == 1)
console.log(dateNow == 1 || 2)
console.log(true == 0)
console.log(true == 1)
console.log(true == 2)
Results: 结果:
false
2
false
true
false
My explanation is that dateNow == 1 || 2
我的解释是
dateNow == 1 || 2
dateNow == 1 || 2
is treated as (dateNow == 1) || 2
dateNow == 1 || 2
被视为(dateNow == 1) || 2
(dateNow == 1) || 2
which is false as we can see. (dateNow == 1) || 2
如我们所见,这是错误的。
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