使用字母数字和仅字母值的混合对 SQL 中的字母数字列进行排序

Question

I have a requirement where I have to apply sort in an SQL query by an Alphanumeric column such that the values in it get sorted like the following:

AD
AH
AK1
B1
B2
B3x
B3y
B11
C1
C6
C12x
UIP

instead of the default way:

AD
AH
AK1
B1
B11
B2
B3x
B3y
C1
C12x
C6
UIP

I was able to write the following SQL statement:

SELECT [MyColumn]
FROM [MyTable]
ORDER BY
    LEFT([MyColumn], PATINDEX('%[0-9]%', [MyColumn]) - 1),
    CONVERT(INT, SUBSTRING([MyColumn], PATINDEX('%[0-9]%', [MyColumn]), LEN([MyColumn]) - (PATINDEX('%[0-9]%', REVERSE([MyColumn]))))),
    RIGHT([MyColumn], PATINDEX('%[0-9]%', [MyColumn]) - 1)

I just need to know how to implement this in a conditional way such that this doesn't get triggered for alpha-only value else it would give error, or if there is a way to make it work with that as well?

PS The environment is SQL Server 2014.

Answer 1

It is a bit of a mess to look at and I agree with Sean Lange that you should look into recording this in more than one field, but you can use case expressions within your order by to have conditional ordering:

declare @t table(c nvarchar(10));
insert into @t values('AD'),('AH'),('AK1'),('B1'),('B2'),('B3x'),('B3y'),('B11'),('C1'),('C6'),('C12x'),('UIP');

select c
from @t
order by
      case when patindex('%[0-9]%', c) = 0
           then c
           else left(c, patindex('%[0-9]%', c) - 1)
      end
      ,case when patindex('%[0-9]%', c) = 0
           then 0
           else convert(int,substring(c,patindex('%[0-9]%', c),len(c) - (patindex('%[0-9]%', reverse(c)))))
      end
      ,right(c,case when patindex('%[0-9]%', c) = 0
                   then 0
                   else patindex('%[0-9]%', c) - 1
               end
      );

Output:

+------+
|  c   |
+------+
| AD   |
| AH   |
| AK1  |
| B1   |
| B2   |
| B3x  |
| B3y  |
| B11  |
| C1   |
| C6   |
| C12x |
| UIP  |
+------+