Spring Boot - 如何将 application.yml 属性定义为 application.properties

Question

I am currently trying to set up an s3 bucket with my Spring Boot webapp for adding/removing images.

The guide I am following uses the following application.yml properties:

amazonProperties:
  endpointUrl: https://s3.us-east-2.amazonaws.com
  accessKey: XXXXXXXXXXXXXXXXX
  secretKey: XXXXXXXXXXXXXXXXXXXXXXXXXX
  bucketName: your-bucket-name

How can I define these properties in my application.properties file?

All help is very much appreciated, thank you!

Answer 1

Try to just split them in different lines in your application.properties :

amazonProperties.endpointUrl= https://s3.us-east-2.amazonaws.com
amazonProperties.accessKey= XXXXXXXXXXXXXXXXX
amazonProperties.secretKey= XXXXXXXXXXXXXXXXXXXXXXXXXX
amazonProperties.bucketName= your-bucket-name

Answer 2

if you're using spring Spring Cloud AWS maven dependency <dependency> <groupId>org.springframework.cloud</groupId> <artifactId>spring-cloud-starter-aws</artifactId> </dependency>

use the following properties in your application.properties file.

cloud.aws.region.static=your region cloud.aws.credentials.accessKey=your access key cloud.aws.credentials.secretKey=your secret key app.awsServices.bucketName=bucketName

refer: https://cloud.spring.io/spring-cloud-static/spring-cloud-aws/1.2.3.RELEASE/multi/multi__basic_setup.html