使用 sequelize 原始查询 node.js 在结果中将 tinyint 字段转换为布尔值

Question

I have problem that when I use a raw query in sequelize which is select query the tinyint fields returned are as integers and not as true / false .

Here is the code:

router.route('/').get(function (req, resp) {
    sequelize.query("select * from territory_device", {model: territoryDevice}).then(result => {
        resp.send(result)
    })
})

And here is the result I recieve:

Although I defined the field is_active as a boolean in the model it gets returned as an integer and I am using MySQL dialect .

Answer 1

The problem is mysql side. Mysql returns 0 or 1 for boolean datatype. You can change the datatype or just handle 0 or 1 in your program

Answer 2

instead of using {raw: true} , you can get Sequelize's wrapper and convert the response using .toJSON() method on the returned response.

then you will get the tinyint parsed as boolean as long as its DataType.BOOLEAN in Sequelize's model object.