[英]Issue with nested ajax call in jQuery
I have a situation where I make an ajax call, on returning from which (successfully), I make an another ajax call with the returned data and submit the page.我有一种情况,我进行了 ajax 调用,在返回时(成功),我使用返回的数据进行了另一个 ajax 调用并提交了页面。 The pseudo code looks something like this:伪代码如下所示:
$.ajax({
url: 'first_page.jsp',
type: 'POST',
dataType: 'JSON',
data: {...}
}).done(function(response) {
$.ajax({
url: '2nd_page.jsp',
type: 'POST',
dataType: 'JSON',
data: {...}
});
thisPage.submit();
});
The inner ajax call is not executed if I do not comment out the 'submit' line.如果我不注释掉“提交”行,则不会执行内部 ajax 调用。 I do not understand the behaviour.我不明白这种行为。 Can someone please help me with this.有人可以帮我解决这个问题。 Thanks谢谢
You need to execute submit on second ajax
sucess.您需要在第二次ajax
成功时执行提交。
For example例如
$.ajax({
url: '',
type: 'GET',
data: {
},
success: function (data) {
$.ajax({
url: '',
type: 'GET',
data: {
},
success: function (data) {
//do your stuff
}
$("input[type='submit']").click(function(event){
event.preventDefault();
$.ajax({
url:'abcd.php',
method:'post',
type:'json',
async:false,
success:function(response){
$.ajax({
url:'abcde.php',
method:'post',
type:'json',
data:{res:response},
success:function(response){
console.log(response);
}
});
$("form").submit();
}
});
});
Try this one.Its working correctly.试试这个。它工作正常。
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