如何检查键的一部分是否在多维数组中

Question

I am looking for a piece of code that can check whether a part of a "word" is inside of a multi-dimensional array. 我正在寻找一段代码，可以检查“单词”的一部分是否在多维数组内。

     foreach($teamMembers as $key => $value){
       if(preg_match('/^1.1./', $key)){
            $countCount += $key;
            $answerCount++;
        }
    }

I've tried to use this, but no luck. 我尝试使用此功能，但没有运气。

I need to count all numbers when the key starts with '1.1.' 当key以“ 1.1”开头时，我需要计算所有数字。 It's inside a multidimensional array. 它在多维数组内。 Maybe that's the reason why it's not working? 也许这就是为什么它不起作用的原因？

The places where I need to get the data from is always different. 我需要从中获取数据的地方总是不同的。 $teamMembers[0] $teamMembers[1] etc. $teamMembers[0] $teamMembers[1]等。

Edit: 编辑：

The 1.1. 1.1. does not contain any wildcards. 不包含任何通配符。 An array looks like this: 数组如下所示：

EDIT: 编辑：

The next lines of code almost completely works. 接下来的几行代码几乎可以正常工作。

$count=0;
foreach($teamMembers[0] as $item){
  if(is_array($item)){
    foreach($item as $k=>$v){
        if(strpos($k,'1.1')===0){
            $count += $v;
        }
     }
   }
 }

But I need $teamMembers[0] to go into the direction of $ teamMembers[0]['antwoord']. Else it'll pick up wrong data. Does anyone know how I can get this implemented? Just putting '['antwoord'] 但是我需要$teamMembers[0]进入$ teamMembers[0]['antwoord']. Else it'll pick up wrong data. Does anyone know how I can get this implemented? Just putting '['antwoord'] teamMembers[0]['antwoord']. Else it'll pick up wrong data. Does anyone know how I can get this implemented? Just putting '['antwoord'] teamMembers[0]['antwoord']. Else it'll pick up wrong data. Does anyone know how I can get this implemented? Just putting '['antwoord'] behind it gives all 0 as output. teamMembers[0]['antwoord']. Else it'll pick up wrong data. Does anyone know how I can get this implemented? Just putting '['antwoord']得到所有0 。

Answer 1

You can iterate each subarray and call array_filter() with strpos() then add that count to your total tally. 您可以迭代每个子array_filter()并使用strpos()调用array_filter() ，然后将该计数添加到总计数中。

Code: ( Demo ) 代码：（演示）

$count=0;
foreach($teamMembers as $item){
    if(is_array($item)){
        $count+=sizeof(array_filter($item,function($k){return strpos($k,'1.1.')===0;},ARRAY_FILTER_USE_KEY));
    }
}
echo $count;

Output: 输出：

This is the same type of method with loops: 这与循环的方法类型相同：

$count=0;
foreach($teamMembers as $item){
    if(is_array($item)){
        foreach($item as $k=>$v){
            if(strpos($k,'1.1.')===0){
                ++$count;
            }
        }
    }
}
echo $count;

Furthermore... 此外...

If you want to target a specific subarray and count how many of those associative elements have a key that starts with a certain substring you can use: 如果要针对特定的子数组并计算有多少个关联元素的键以某个子字符串开头，则可以使用：

function count_keys_beginning_with($array,$substring){
    return sizeof(array_filter($array,function($k)use($substring){return strpos($k,$substring)===0;},ARRAY_FILTER_USE_KEY));
}
echo count_keys_beginning_with($teamMembers['antwoord'],'1.1.');
// output: 3

Or without a custom function call: 或没有自定义函数调用：

$answer_count=sizeof(array_filter($teamMembers['antwoord'],function($k){return strpos($k,'1.1.')===0;},ARRAY_FILTER_USE_KEY));
echo $answer_count;
// output: 3

Answer 2

array_walk_recursive + strpos solution: array_walk_recursive + strpos解决方案：

$teamMembers = [
    'responderScoRev' => 'Score',
    'antwoord' => ['1.2. text' => 1, '1.1.2 text' => 1, '1.1.3 text' => 1],
    '1.1.3' => 3
    ];

$cnt = 0;
array_walk_recursive($teamMembers, function($v, $k) use(&$cnt){
   if (strpos($k, '1.1.') === 0) $cnt++; 
});

print_r($cnt);

如何检查键的一部分是否在多维数组中

问题描述

2 个解决方案

解决方案1
1 已采纳 2018-02-20 22:45:49

解决方案2
1 2018-02-20 23:02:23

如何检查键的一部分是否在多维数组中

问题描述

2 个解决方案

解决方案1 1 已采纳 2018-02-20 22:45:49

解决方案2 1 2018-02-20 23:02:23

解决方案1
1 已采纳 2018-02-20 22:45:49

解决方案2
1 2018-02-20 23:02:23