如何通过urlopen处理400错误请求？

Question

I use this piece of code to generate various statistics:

uClient = urlopen(finalURL)
page = uClient.read()
uClient.close()
obj = json.loads(page)
return obj

I have a list of everything that needs to be generated, but some of those URL do not exist anymore, but the file is too big to go thourgh it by hand. Once it returns Bad request, the script runs into error, but I would like it to just pass that URL if it is a bad request and continue without existing.

Answer 1

Try to use exception handling

try:
    uClient = urlopen(finalURL)
    page = uClient.read()
    uClient.close()
    obj = json.loads(page)
    return obj
except urllib2.HTTPError as e:
    if e.code == 404:
        print "Not found"

Answer 2

I tried this exception handling by @mkHun:

try:
   uClient = urlopen(finalURL)
   page = uClient.read()
   uClient.close()
   obj = json.loads(page)
   return obj
except ValueError:
  print "Not found"

but instead of using ValueError, I used urllib2.HTTPError as suggested by @tmadam which ultimately solved my problem. Thank you everyone!