在Python中将第一列第一行替换为字符串'date'

Question

I have csv file and I have insert current date in the first column.

My code is here:

import datetime
from datetime import datetime, timedelta
date=datetime.strftime(datetime.now(), '%Y%m%d')

df=pd.read_csv('C:/Paramter_Generation/LTERaw/'+date+'/ENodeBAlgoSwitch_1.csv',header=None,low_memory=False

  df.insert(0,'Date',date)
  df.to_csv('C:/Paramter_Generation/LTERaw/'+date+'/ENodeBAlgoSwitch_1.csv',header=None,index= False)

The dataframe is here:

  1     20180222  ne_name             handover_algo_switch   
  0     20180222      001  1111000000101000000001000000000   
  2     20180222      002  1111000000101000000001000000000   
  3     20180222      003  1111000000101000000001000000000   

Now I want to change the first column first row '20180222' to string 'date'.

I know following code can change the first column first row to the string 'date':

    df.set_index('Date', inplace=True)
    df.to_csv('C:/Paramter_Generation/LTERaw/'+date+'/'+names+'')

But after execute that, the column ne_name '001','002','003' will be replace to '1','2','3.' I don't want to change other colume property.

Can anyne have idea how to change the first column first row '20180222' to string 'date' and do not change other column property?

Answer 1

It seems need:

f = 'C:/Paramter_Generation/LTERaw/'+date+'/ENodeBAlgoSwitch_1.csv'
df = pd.read_csv(f, dtype={'ne_name':str})
df.index = date

df.to_csv(...)