在不同的shell中执行函数

Question

I usually zsh . I want to execute a function in bash and return back to my original shell. I can do this manually, but I want to automate it. How can I do that?

For example, I am on zsh. I want to execute func , which is a function() in bigscript.sh file. I am sourcing the bigscript.sh file in my .zshrc I tried adding shebang !#/bin/bash in the bigscript.sh file, but that does not change the shell. I tried another approach of putting function in a standalone function.sh file and added shebang to it. It worked. However, I do not want to break the files into smaller .sh files.

So, any suggestions on changing the shell for a single function..?

Answer 1

If the function is written in bash, you can not - in general - execute it from Zsh, since bash and Zsh are different languages. Of course since there are some similarities, it is possible to write functions which work the same on bash on Zsh, I wouldn't rely on it. Even if your function happens to be a "compatible" one at the moment, if someone modifies this function later, he possibly won't be aware that this function will be used outside of the bash context and change it in a way so that it doesn't run or - even worse - behaves differently under Zsh.

So the only way would be to write an interface bash script, which sources the file where this function is defined, and executes it - something like

#!/bin/bash
# Interface script to call bash function foo from other languages
. file-which-defines-function-foo
foo "$@"