从我的三个表中选择数据

Question

I have three tables, one named album , while the other one is soundtrack and last but definitely not the least, is the artist .

Under one album is more than one track (obviously) and an artist name...

So this is how it should look like:
Desired Output:

 |---------------------|
 |AlbumName by Charlie |
 |---------------------|
 | 1. See you again    |
 |---------------------|
 | 2. One call Away    |
 |---------------------|
 | Album by Ed Sheeran |
 |---------------------|
 | 1. Perfect          |
 |---------------------|
 | 2. Dive             |
 |---------------------|

And below is mysqli_fetch_array() that I used along side with while-loop to populate the <table> tag.

$query = "SELECT a.* AS Album, b.* AS Track, c.* AS Artist 
        FROM album a 
        INNER JOIN track b ON a.album_id=b.album_id 
        INNER JOIN artist c ON a.artist_id=c.artist_id 
        ORDER BY a.album_id ASC";

$result = mysqli_query($con, $query);
$c=0;
while($row = mysqli_fetch_assoc($result)) {
   $album = $row['Album']." (".$row['Artist'].") ";
   $track = $row['Track'];
}

The problem is, when I ran this code... I could only get this result...

|---------------------|
|AlbumName by Charlie |
|---------------------|
|  1. See you again   |
|---------------------|
|  2. One call away   |
|---------------------|
|  1. Perfect         |
|---------------------|
|  2.  Dive           |
|---------------------|

It got the list of the soundtracks, including the soundtrack's ID right, however, things didn't do well on the Album Name

I want it just to look like the Desired Output . Any ideas? I've tried to search stackoverflow, but it seems it couldn't direct me on the same question, so I made my own. Please forgive (do not flag) me if it had an existing already, its just that I didn't know where to find it. And pleeeeease... I need an immediate and working answer. Thanks guys!

As for DATABASE Structure

album = {album_id, artist_id,album_title}
artist = {artist_id, artist_name}
track = {song_id, album_id, song_title}

UPDATE!
Okay, so this goes a little bit out of control. When I tried @swellar's suggestion this what happened. And when I undo it, the output remains the same. See the result below...

|---------------------|
|AlbumName by Charlie |
|---------------------|
|  1. See you again   |
|---------------------|
|AlbumName by Charlie |
|---------------------|
|  2. One Call Away   |
|---------------------|
|AlbumName by Charlie |
|---------------------|
|  1.  Perfect        |
|---------------------|
|AlbumName by Charlie |
|---------------------|
|  2.   Dive          |
|---------------------|

What I want is to give each Album one or more than soundtrack but it get so messed up each time I dare to change the query . How can I sanitize the mysqli_fetch_array() for it to display the desired output?

Answer 1

Here is your SQL

Notice I've put 3 order by in there. First by the artist name, which would keep all artist's stuff grouped together, then by album name and then by song id.

$sql = "SELECT a.album_title AS Album,
               t.song_title AS Track,
               t.song_id AS ID,
               n.artist_name AS Artist
        FROM album AS a
            INNER JOIN track AS t
                ON a.album_id = t.album_id
            INNER JOIN artist AS n
                ON a.artist_id = n.artist_ID
        ORDER BY n.artist_name ASC,
                 a.album_id ASC,
                 t.song_id ASC";


/*
That SQL will generate the following array

Array
(
    [Album] => AlbumName
    [Track] => See you again
    [ID] => 1
    [Artist] => Charlie
)
Array
(
    [Album] => AlbumName
    [Track] => One call Away
    [ID] => 2
    [Artist] => Charlie
)
Array
(
    [Album] => Album
    [Track] => Perfect
    [ID] => 1
    [Artist] => Ed Sheeran
)
Array
(
    [Album] => Album
    [Track] => Dive
    [ID] => 2
    [Artist] => Ed Sheeran
)
*/

Below is your while loop

<table>
<?php
// Some placeholders
$album = null;

while($row = mysqli_fetch_assoc($result))
{
    if($row['Album'] !== $album)
    {
?>
    <tr>
        <td style="border: 1px solid #000000; background-color: #dedede;"><?php echo $row['Album']; ?> by <?php echo $row['Artist']; ?></td>
    </tr>
    <tr>
        <td style="border: 1px solid #000000;"><?php echo $row['ID']; ?>: <?php echo $row['Track']; ?></td>
    </tr>
<?php
    }
    else
    {
?>
    <tr>
        <td style="border: 1px solid #000000;"><?php echo $row['ID']; ?>: <?php echo $row['Track']; ?></td>
    </tr>
<?php
    }

   $album = $row['Album'];
}
?>
</table>

Overall Output is:

 <table> <tr> <td style="border: 1px solid #000000; background-color: #dedede;">AlbumName by Charlie</td> </tr> <tr> <td style="border: 1px solid #000000;">1: See you again</td> </tr> <tr> <td style="border: 1px solid #000000;">2: One call Away</td> </tr> <tr> <td style="border: 1px solid #000000; background-color: #dedede;">Album by Ed Sheeran</td> </tr> <tr> <td style="border: 1px solid #000000;">1: Perfect</td> </tr> <tr> <td style="border: 1px solid #000000;">2: Dive</td> </tr> </table> 

There are better ways to go around doing this, but not knowing your work environment, skills, requirements, other code, w/e this is the best quick and dirty solution for you to base your solution of. This works to what you requested.