[英]Spring boot JPA save manytomany relationship
I am trying to store a manytomany relationship but it not stores the relationship.我正在尝试存储多对多关系,但它不存储关系。
The following code has generated 3 tables.以下代码生成了 3 个表。
Soldier, medal and soldier_medals.士兵、奖章和士兵奖章。
The service just make a call to a CRUD Interface with save(soldier).该服务只需使用 save(soldier) 调用 CRUD 接口。
It stores correctly the soldier, but it not fill any row at the soldier_medals table.它正确地存储了士兵,但它没有填充士兵奖章表中的任何行。
This is the JSON I send to the server:这是我发送到服务器的 JSON:
{
"abbreviatedSequence": "XDF",
"medals": [
{
"name": "Purple",
"id": 1
},
{
"name": "Red",
"id": 2
}
],
"sequence": "XDFREE",
"name": "Savier"
}
Employee.java雇员.java
@Entity(name="employees")
@Inheritance(strategy=InheritanceType.SINGLE_TABLE)
public class Employee {
@Id
@GeneratedValue(generator="increment")
@GenericGenerator(name="increment", strategy = "increment")
private Long id;
private String name;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
Soldier.java士兵.java
@Entity(name="soldier")
public class Soldier extends Employee{
private String sequence;
private String abbreviatedSequence;
@ManyToMany(fetch = FetchType.LAZY, mappedBy = "soldiers")
private List<Medal> medals;
public List<Medal> getMedals() {
return medals;
}
public void setMedals(List<Medal> medals) {
this.medals = medals;
}
public String getSequence() {
return sequence;
}
public void setSequence(String sequence) {
this.sequence = sequence;
}
public String getAbbreviatedSequence() {
return abbreviatedSequence;
}
public void setAbbreviatedSequence(String abbreviatedSequence) {
this.abbreviatedSequence = abbreviatedSequence;
}
}
Medal.java奖章.java
@Entity
@Table(name = "medal")
public class Medal {
@Id
@Column(name = "ID")
@GeneratedValue(strategy = GenerationType.AUTO, generator = "medal_seq")
@SequenceGenerator(name = "medal_seq", sequenceName = "medal_seq", allocationSize = 1)
private Long id;
@Column(name = "NAME", length = 50, unique = true)
@NotNull
@Size(min = 3, max = 50)
private String name;
@ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinTable(name = "soldier_medals", joinColumns = {
@JoinColumn(name = "medal_id", nullable = false, updatable = false) },
inverseJoinColumns = { @JoinColumn(name = "soldier_id",
nullable = false, updatable = false) })
private List<Soldier> soldiers;
public List<Soldier> getSoldiers() {
return soldiers;
}
public void setSoldiers(List<Soldier> soldiers) {
this.soldiers = soldiers;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
SoldierController.java士兵控制器.java
@RestController
public class SoldierController {
@Autowired
private SoldierService soldierService;
@RequestMapping(value="/api/contextsource/soldier",method= RequestMethod.POST)
public Soldier addSoldier(@RequestBody Soldier soldier) {
return soldierService.addSoldier(soldier);
}
}
I was persisting the entity with in the wrong order.我以错误的顺序坚持实体。 This is how I solved it.
这就是我解决它的方法。
@RequestMapping(value="/api/contextsource/soldier",method= RequestMethod.POST)
public Soldier addPeptide(@RequestBody Soldier soldier) {
for(Medal s: soldier.getMedals()) {
Medal ss = medalService.getMedalById(s.getId());
ss.getMedals().add(soldier);
medalService.addMedal(ss);
}
return null;
}
Did you try this in Soldier entity class like medal entity class:您是否在像奖章实体类这样的士兵实体类中尝试过这个:
@ManyToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
@JoinTable(name = "soldier_medals", joinColumns = {
@JoinColumn(name = "soldier_id", nullable = false, updatable = false) },
inverseJoinColumns = { @JoinColumn(name = "medal_id",
nullable = false, updatable = false) })
private List<Medal> medals;
instead of this :而不是这个:
@ManyToMany(fetch = FetchType.LAZY, mappedBy = "soldiers")
private List<Medal> medals;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.