如何获得 TypeScript 中数字的总位数？

Question

Declaration of a number variable called temp in TypeScript:在 TypeScript 中声明一个名为temp的数字变量：

temp: number = 0.123;

How can I get a count of the total number of digits in a number (which is 3)?我怎样才能得到一个数字的总位数（即 3）？

Answer 1

If I understood correct, you want the part after .如果我理解正确，您需要. . .

You can parse it into a string, split by .你可以解析成一个字符串， split的. and count the string length of the second item.并计算第二项的字符串长度。

 const temp = 0.123; const tempArray = temp.toString().split('.'); const length = tempArray[1].length; console.log(length);

Answer 2

in typescript simply use:在打字稿中只需使用：

this.number.toString().split('.'))[1].length this.number.toString().split('.'))[1].length

Where this.number is Type of Number this.number 是数字类型

Answer 3

Use this Regexp \\.\\d+使用这个正则表达式\\.\\d+

 var temp = 0.123; var regex = new RegExp('\\\\.\\\\d+', 'g'); console.log(temp.toString().match(regex).pop().length - 1);