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C ++按值返回vs按引用返回

[英]c++ return by value vs return by reference

If I have two functions like: 如果我有两个功能,例如:

1. 1。

vector<Student_Info> extract_failed(vector<Student_Info>& students) {
    return students;
}

2. 2。

vector<Student_Info>& extract_failed(vector<Student_Info>& students) {
    return students;
}

Is it correct to say that function 1 is returning by value , which means a copy of students will be created and returned and function 2 is returning by reference ? 说函数1 returning by value是正确的,这意味着将创建一个students副本并返回并且函数2 returning by reference吗?

Is it correct to say that function 1 is returning by value, which means a copy of students will be created and returned and function 2 is returning by reference? 说函数1按值返回是否正确,这意味着将创建并返回一个学生副本,而函数2按引用返回?

Yes, it is correct. 是的,这是正确的。 Another way to phrase it, which I prefer, is to say that 1 returns a value, and 2 returns a reference. 我更喜欢用另一种说法来表达它,就是说1返回一个值,而2返回一个引用。

YES

Although 2. in its current form would make sence if you plan to use the return value (something like print(extract_failed(students)); or for(const auto& s : extract_failed(students) ). 虽然2.如果您打算使用返回值(例如print(extract_failed(students));for(const auto& s : extract_failed(students) ),则会以当前的形式出现。

Meanwhile, some scenarios may be confusing, since you can do something like 同时,某些情况可能会令人困惑,因为您可以执行以下操作

auto& new_students = extract_failed(students);

and you'll have two names in the same scope for the same vector. 并且您将在同一范围内为相同的向量使用两个名称。

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