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方法查找javascript深度数组对象RN react native

[英]method find javascript deep array object RN react native

Here is a part of my object 这是我对象的一部分

const category = {
    fr: {
        list: [
            {id: 1, label: 'coucou'},
            {id: 2, label: 'moi'},
            {id: 3, label: 'ici'},
            {id: 4, label: 'maintenant'},
            {id: 5, label: 'demain'},
]}}
const lang = fr;
const anyId = 3;

I don't know why when doing the following: 我不知道为什么执行以下操作:

const result = category[lang].list.find(item => item.id === anyId) console.log(result)

Throws the following: 引发以下情况:

// undefined category[lang].list.find(item => item.id === anyId) is not a function, or just undefined //未定义的category [lang] .list.find(item => item.id === anyId)不是函数,或者只是未定义

same result for .map or .filter .map或.filter的结果相同

  • console.log(category) returns no error console.log(category)返回错误
  • console.log(category[lang]) returns no error console.log(category[lang])返回错误
  • console.log(category[lang].list) returns no error console.log(category[lang].list)返回错误

but anything else will return an error. 但其他任何东西都会返回错误。 It drives me crazy, any help will be highly appreciated. 这让我发疯,任何帮助将不胜感激。

Use const lang = "fr" instead of const lang = fr , because fr is an undefined variable but "fr" is a string. 使用const lang = "fr"而不是const lang = fr ,因为fr是未定义的变量,而"fr"是字符串。 So you'll get category["fr"] instead of category[fr] . 因此,您将获得category["fr"]而不是category[fr]

 const category = { fr: { list: [ {id: 1, label: 'coucou'}, {id: 2, label: 'moi'}, {id: 3, label: 'ici'}, {id: 4, label: 'maintenant'}, {id: 5, label: 'demain'}, ]}} const lang = "fr"; const anyId = 3; const result = category[lang].list.find(item => item.id === anyId) console.log(result) 

You want category.fr not just fr , as the variable fr does not exist. 您不希望category.fr只是fr ,因为变量fr不存在。

Now that lang contains your fr object, you can simply do a .find() on lang.list as below: 现在, lang包含您的fr的对象,你可以简单地做一个.find()lang.list如下:

 const category = { fr: { list: [ {id: 1, label: 'coucou'}, {id: 2, label: 'moi'}, {id: 3, label: 'ici'}, {id: 4, label: 'maintenant'}, {id: 5, label: 'demain'}, ]}} // Fill param from a variable, or anything, as long as it's a string: const param = 'fr'; // Use brackets here, as you want `category.fr` and not `category.param`: const lang = category[param]; //Or you can simply use: //const lang = category.fr; //If this is not a parameter, or user input const anyId = 3; console.log(lang); console.log(lang.list.find(item => item.id === anyId)); 

It works on mdn sandbox 它在mdn沙箱上工作

const category = {
    fr: {
        list: [
            {id: 1, label: 'coucou'},
            {id: 2, label: 'ici'},
            {id: 3, label: 'demain'},
            {id: 4, label: 'matin'},
          ]
    }
};
var lang ='fr';
var catID = 3;
console.log(lang);
console.log(catID);
console.log(category);
console.log(category[lang]);
console.log(category[lang].list);
var found = category[lang].list.find(function(element) {
   return element.id === catID;
});

console.log(found.label); // demain

just add a return inside the callback function, but it still doesn't work on react-native so the problem remains 只需在回调函数中添加return,但它仍然无法在react-native上正常工作,因此问题仍然存在

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