函数内的函数不起作用

Question

I want to call a function, which has a function inside it. Why does this code not work? It has to look like this, because I've created a XMLHttpRequest inside getNumber(). The code below is just an example.

getNumber();

function getNumber()
{
    otherFunction = function()
    {
        console.log("It's working!");
    }
}

Answer 1

It does "work" (well, so long as you aren't using strict mode — always use strict mode! — since it depends on implicit globals).

You call getNumber , which defines a global variable called otherFunction and uses a function expression to assign a value to it.

If you ever called otherFunction ( you don't! ), it would log It's working .

As it stands, nothing in your code should generate any output.

 getNumber(); function getNumber() { otherFunction = function() { console.log("It's working!"); } } otherFunction();