PHP如何在链接中保留所有GET变量？

Question

I have some PHP code that generates dynamic tables of data on the fly. By clicking various links you "refine" the tables of data. What I'd like is each of these links to retain the current GET information and add to it. IE:

$allPreviousVars = ???; // Could be 20+ vars
echo "<a href='".$allPreviousVars."&newVar=2'>Link</a>";

I can think of ways to do it by iterating through $_GET with a loop, but surely there is a quicker way to do this?

Answer 1

How about $_SERVER["QUERY_STRING"]?

EDIT: Since you were kind enough to give me credit for this answer, I should add one thing. You should wrap the above variable in htmlspecialchars() before you output it. Otherwise someone could type a URL with "> in it, and it would break your link.

Answer 2

I do this as follows:

<?php echo http_build_query(array_merge($_GET, array('foo'=>'bar', 'foo2'=>'bar2')); ?>

Note that any existing 'foo' or 'foo2' keys would be replaced.

Answer 3

Use http_build_query() if you need to generate a query-string from a modified array. If you just want the querystring sent to the current page, do as suggested and use $_SERVER["QUERY_STRING"].

Answer 4

I would probably do this:

$query = mySanitizeFunction($_GET);
$url = http_build_query($query) . '&newVar=2';

Answer 5

你最好的选择是，如你所建议的那样，循环遍历$_GET的内容，从现有查询参数和被覆盖的位的混合构造URL。