[英]Can't View result while joining 3 tables
I have some trouble when I Joining 3 tables, I use mysqli procedural. 我在加入3个表时遇到麻烦,我使用mysqli程序。 here's my query..
这是我的查询。
$select = $connection->conn->query('SELECT * FROM master_beli, supplier, karyawan WHERE supplier.id_supplier = master_beli.id_supplier AND karyawan.id_karyawan = master_beli.id_karyawan');
After that I viewing with this code 之后,我用这段代码查看
while($fetchData = $select->fetch_array()){
echo $fetchData['id_karyawan'].'<br>';
}
I don't know where the problem is, because I use this query a few months ago and it's worked, but now isn't work.. 我不知道问题出在哪里,因为几个月前我使用了此查询并且它已经工作了,但现在却行不通。
SELECT master_beli.id_supplier,master_beli.id_karyawan
FROM master_beli
join supplier on supplier.id_supplier = master_beli.id_supplier
join karyawan on karyawan.id_karyawan = master_beli.id_karyawan;
it work on mysql 它在mysql上工作
Could be your issue is related to the ambiguity of the column name id_karyawan
present in two tables try use an explicit alias or a explict column naming eg : 可能是您的问题与两个表中存在的列名
id_karyawan
的歧义有关,请尝试使用显式别名或显式列命名,例如:
$select = $connection->conn->query('SELECT master_beli.id_karyawan
FROM master_beli
INNER JOIN supplier ON supplier.id_supplier = master_beli.id_supplier
INNER JOIN karyawan ON karyawan.id_karyawan = master_beli.id_karyawan');
and as suggested in the code above you should use explicit join sintax ..for better readibilty (the use of implict join sintax is not more promoted in sql) 并按照上面的代码中的建议,您应该使用显式联接sintax ..以获得更好的可读性(在SQL中不提倡使用隐式联接sintax)
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