如何在一行中打印for循环的所有单词

Question

I have following set of data.

set = [('john', 'm', 23), ('maria', 'f', 17), ('john', 'm', 45), 
       ('stacy', 'f', 19), ('stacy', 'f', 21), ('mary', 'f', 32)]

I want my output to look like:

John: m(23) m(45)
Maria: f(17)
Stacy: f(19) f(21)

Right now my output looks like this with the following code.

Output:

John:   m (23) 
Maria:   f (17) 
John:   m (45) 
Stacy:   f (19) 
Stacy:   f (21)

Code:

for ind in set:
    i = ind[0]
    if i == "john":
        print("John:"," ", str(ind[1]), "({0}) ".format(str(ind[2])))
    elif  i == "maria":
        print("Maria:"," ", str(ind[1]), "({0}) ".format(str(ind[2])))
    elif i == "stacy":
        print("Stacy:", " ", str(ind[1]), "({0}) ".format(str(ind[2])))

Answer 1

Try this (it only prints for john, maria and stacy) :

data = [('john', 'm', 23), ('maria', 'f', 17), ('john', 'm', 45),
        ('stacy', 'f', 19), ('stacy', 'f', 21), ('mary', 'f', 32)]

permitted_names = ['john', 'maria', 'stacy']
output = {}
for name, gender, age in data:
    if name not in permitted_names:
        pass
    elif name not in output:
        output[name] = '{0}({1})'.format(gender, age)
    else:
        output[name] += ' {0}({1})'.format(gender, age)

for name, value in output.items():
    print("{0}: {1}".format(name, value))

Output:

john: m(23) m(45)
maria: f(17)
stacy: f(19) f(21)

Answer 2

You should first collect the data for each person, and then you can print for each person, one at a time like:

Code:

data = [('john', 'm', 23), ('maria', 'f', 17), ('john', 'm', 45),
       ('stacy', 'f', 19), ('stacy', 'f', 21), ('mary', 'f', 32)]

# collect per person, except Mary.  We don't like Mary
as_dict = {}
for datum in data:
    as_dict.setdefault(datum[0], []).append(datum)

# print each person, except Mary.  We don't like Mary.
for name, items in as_dict.items():
    if name in set('john stacy maria'.split()):
        msg = '{}: '.format(name) + ' '.join('{} ({})'.format(i[1], i[2])
                                             for i in items)
        print(msg)

Results:

john: m (23) m (45)
mary: f (32)
stacy: f (19) f (21)
maria: f (17)

Answer 3

You can use python's defaultdict for this:

In [37]: from collections import defaultdict

In [38]: data = [('john', 'm', 23), ('maria', 'f', 17), ('john', 'm', 45),
    ...:        ('stacy', 'f', 19), ('stacy', 'f', 21), ('mary', 'f', 32)]

In [39]: d = defaultdict(list)
In [40]: for name, *rest in data:
    ...:     d[name].append(rest)

In [41]: for name, value in d.items():
    ...:     if name in ('john', 'maria', 'stacy'):
    ...:         strvalues = (' {}({})'.format(a, b) for a, b in value)
    ...:         print('{}: {}'.format(name, ''.join(strvalues)))
john:  m(23) m(45)
maria:  f(17)
stacy:  f(19) f(21)

Answer 4

Here's a different approach in which you collect the names of all person from your input list, then you collect and combine all information associated with each person and finally you print these information:

inSet = [('john', 'm', 23), ('maria', 'f', 17), ('john', 'm', 45), 
       ('stacy', 'f', 19), ('stacy', 'f', 21), ('mary', 'f', 32)]

# Get names of people
nameSet = sorted(set([info[0] for info in inSet]))

# Get all info associated with each of these people
displayInfo = [ " ".join(["".join([info[1], '(' + str(info[2]) + ')']) for info in inSet if name==info[0]]) for name in nameSet]

# Print these information, after capitalizing first letter of each name.
for info in zip(map(str.title,nameSet),displayInfo):
print(": ".join(info))

Output:

John: m(23) m(45)
Maria: f(17)
Mary: f(32)
Stacy: f(19) f(21)