[英]C program - find largest sequence in array
Given this example : 给出这个例子:
int arr[3][7] = { {1,0,0,1,1,1,1}, //should output 4
{0,1,1,1,1,0,1}, //should output 4
{0,0,1,1,1,1,1}}; //should output 5
Find the largest sequence containing number 1 , and print line index and number of 1 . 查找包含数字1的最大序列,并打印行索引和数字1 。
Do not count total numbers of 1 in each line. 不要 在每行中 计算总数 1 。 Only if they are one after another .
只有他们一个接一个 。
here is my approach : 这是我的方法:
int main(){
int i,j,c=0,count=0;
int arr[3][7] = { {1,0,0,1,1,1,1}, //output 4
{0,1,1,1,1,0,1}, //output 4
{0,0,1,1,1,1,1}}; // output 5
for(i=0; i<3; i++){
for(j=0; j<7; j++){
if(arr[i][j] == 1){
c++;
} else if( arr[i][j] == 0 && c > count ) {
count = c;
c = 0;
}
}
printf("%d\n", count);
}
return 0;
}
What i want to get as output now is 4,4,5 but i am getting 1,4,5. 我现在想要得到的输出是4,4,5,但是我正在得到1,4,5。
SOLUTION thanks to https://stackoverflow.com/users/1228887/twain249 解决方案感谢https://stackoverflow.com/users/1228887/twain249
int main(){
int i,j,c=0,count=0;
int arr[3][7] = { {1,1,0,1,1,1,1}, //output 4
{0,1,1,1,1,0,1}, //output 4
{0,0,1,1,1,1,1}}; // output 5
for(i=0; i<3; i++){
for(j=0; j<7; j++){
if(arr[i][j] == 1){
c++;
} else {
count = c;
c = 0;
}
}
if(c > count){
count = c;
}
printf("%d\n", count);
c=0;
}
return 0;
}
You forgot to handle the case where the longest sequence is the end of the list 您忘记处理最长序列在列表结尾的情况
after the inner j
loop add the following 在内部
j
循环之后,添加以下内容
if (c > count) {
count = c;
}
Also you forgot to add a clear after each check. 您也忘记在每次检查后添加透明纸。
After the printout add 打印输出后添加
c = clear = 0;
EDIT: 1 more error. 编辑:另外1个错误。 You need to reset
c
even if the new sequence isn't the longest. 即使新序列不是最长的,也需要重置
c
。
Change the else if into 如果更改为else
else if (arr[i][j] == 0) { // If isn't necessary if 0/1 are your only options
{
if (c > count) {
count = c;
}
c = 0;
}
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