从sql中的2列中仅选择不同的值

Question

I have a Table in my database. I need only 2 columns from that entire database. Also, I need the distinct values from the two columns. The data is as follows:

ID          DATE
00432CDE    1/4/2016
64031QCL    1/4/2016
64031QCL    1/5/2016
64031QCL    1/6/2016
817176AA    1/4/2016
817176AA    1/5/2016
55818FAN    1/4/2016
55818FAN    1/5/2016
92912QAA    1/4/2016
92912QAA    1/5/2016
532621AA    1/4/2016
532621AA    1/5/2016
05344AAN    1/4/2016
05344AAN    1/5/2016
17305EFN    1/4/2016

As you can see there are multiple date values and because of that IDs are duplicated. I want to write a code where I can get the last date along with the ID. So the columns should look like this:

ID          DATE
00432CDE    1/4/2016
64031QCL    1/6/2016
817176AA    1/5/2016
55818FAN    1/5/2016
92912QAA    1/5/2016
532621AA    1/5/2016
05344AAN    1/5/2016
17305EFN    1/4/2016

Thank you!

Answer 1

Use an aggregate on your DATE column to choose which one to display. You want MAX() :

SELECT ID, MAX(DATE)
FROM yourTable
GROUP BY ID

Note: Grouping by all non-aggregated columns achieves the same result as DISTINCT , so you won't need the DISTINCT keyword.