grep 特定的正则表达式

Question

I am trying to print out every string that starts with three 0's, ends with three 1's and has zero or more 0's in between.

I was given a file with one large string, with XXX separating the different string I needed to check.

I used sed to break up the string into separate lines wherever there is XXX, but I am trying pipe it into a grep with a specific regular expressions to display only the patterns that I want.

sed "blah blah" | grep 000*111

This displays strings like "1", "111", "000". What wold the regex be to get this specific pattern? Or can I not use grep with a regex like this?

Answer 1

Try this :

sed "blah blah" | fgrep '000*111'

$ whatis fgrep

fgrep (1) - print lines matching a pattern

aka literal, not regex