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如何在mysql查询上写一个php变量

[英]how to write a php variable on a mysql query

我需要正确编写我的php变量。

$query2 = mysqli_query($con,"SELECT * FROM palettes LIMIT '$starting_number, $palettes_per_page'");

I don't think you want single quotes on your LIMIT parameters. 我认为您不希望在LIMIT参数上使用单引号。 One way is to use . 一种方法是使用。 to concatenate strings. 连接字符串。

Since $starting_number and $palettes_per_page are integers, you do not need to escape them. 由于$starting_number$palettes_per_page是整数,因此不需要转义它们。 If they were strings, wrap them in mysqli_real_escape_string or mysqli_escape_string to escape special characters. 如果它们是字符串,则将它们包装在mysqli_real_escape_stringmysqli_escape_string以转义特殊字符。

$query2 = mysqli_query( $con,
             "SELECT * FROM palettes LIMIT " .
             $starting_number .
             "," .
             $palettes_per_page );

Just remove the single quote, because double quote can read variable's value 只需删除单引号,因为双引号可以读取变量的值

$query2 = mysqli_query($con,"SELECT * FROM palettes LIMIT $starting_number, $palettes_per_page");

Hope this works for you 希望这对你有用

您可以使用参数化查询,也可以避免使用mysqli_real_escape_string

$stmt = $conn->prepare("SELECT * FROM palettes LIMIT ?, ?'"); $stmt->bind_param("ii", $starting_number, $palettes_per_page); $stmt->execute();

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