从列表中删除包含小写字母和null的元素

Question

I have a list that contains words, numbers & some random characters.I want to remove elements that contain other than UPPERCASE, Punctuation & Digits.

list_of_words =  ['S I NGHVI', '', 'MGANPAT', '/', '', '', 'q', 'gq6', '14', 'A -_']
for i in list_of_words:
    for j in i:
        if ord(j) not in range(65,91): # for shortlisting A-Z ascii values
            del list_of_words[i]

is throwing me error like this: TypeError: list indices must be integers or slices, not str

Output I want:

list_of_words = ['S I NGHVI', 'MGANPAT', '/', '14', 'A -_']

Answer 1

Answer for first version of question

To get "only CAPITAL letter words & numbers" :

>>> [w for w in list_of_words if w.isupper() or w.isdigit()]
['S I NGHVI', 'MGANPAT', '14', 'A -_']

Answer 2

Simply do the following:

from string import *
list_of_words = [word for word in list_of_words if all([letter in punctuation+ascii_uppercase+digits+' ' for letter in word]) and word]

---

>>> from string import *                                                        
>>> list_of_words =  ['S I NGHVI', '', 'MGANPAT', '/', '', '', 'q', 'gq6', '14', 'A -_']
>>> list_of_words = [word for word in list_of_words if all([letter in punctuation+ascii_uppercase+digits+' ' for letter in word])]
>>> list_of_words
['S I NGHVI', 'MGANPAT', '/', '14', 'A -_']
>>> 

---

You have a couple issues in your code:

1. Do not use del to remove from a list, you can use .remove() , .pop() , or simply overwrite the list.
2. list_word is not defined, perhaps you meant list_of_words ?
3. Using ord is not as readable and concise as using the string module. Simply import string and call dir(string) to see the various predefined character sets you can access.
4. You are using is wrong; is compares the id s of two objects. In this case, you can simply omit it and use not in .