postgresql作为json结果一对多，如何过滤？

Question

I have a simple db structure with a one to many relationship

CREATE TABLE customer (
  id                              SERIAL PRIMARY KEY,
  email                           TEXT,
  first_name                      TEXT,
  last_name                       TEXT
);

CREATE TABLE customer_address (
  id              SERIAL PRIMARY KEY,
  customer_id     INTEGER                NOT NULL,
  street_name     TEXT                   NOT NULL,
  street_number   TEXT                   NOT NULL,
  zip_code        TEXT                   NOT NULL,
  city            TEXT                   NOT NULL
);

For my application I want to return each customer with all its addresses as one row, whereby I encapsulate all the addresses in a json array. This is done like this:

SELECT customer.*, 
       addresses 
FROM   customer 
       left join (SELECT 
Array_to_json(Array_agg( 
Json_build_object('id', address.id, 'street_name', address.street_name, 'street_number', address.street_number, 'zip_code', address.zip_code, 'city', address.city))) AS addresses,
address.customer_id 
AS customer_id 
 FROM   customer_address AS address 
 GROUP  BY address.customer_id) addresses 
       ON addresses.customer_id = customer.id 
join customer_address 
  ON customer_address.customer_id = customer.id 

This works fine and gives me a resultset with for each result an element called addresses containing a JSON array of all the customer's addresses.

Now I would like to select all customers (with all of their addresses) whose street_name is like a certain search term. And I can't get it to work. How can I select full records including all addresses inlined when one address has a street name containing a certain value (matched with an ILIKE ) ?

I tried adding: WHERE customer_address.street_name LIKE 'Ro' , and while this works, if I replace this where statement with something completely different such as WHERE customer.id > 0 I get doubles in the result set

Here is an sql Fiddle to play around in:

http://sqlfiddle.com/#!17/0e818/4

Answer 1

This join condition looks wrong:

JOIN customer_address ON customer_address.id = customer.id

Shouldn't it be

JOIN customer_address ON customer_address.customer_id = customer.id

Here is the fiddle: http://sqlfiddle.com/#!17/2fff0/6

Following the discussions on the original answer, here is the final solution that addresses the raised issues:

http://sqlfiddle.com/#!17/2fff0/25

Answer 2

Does this cover your expected result?

 SELECT customer.*,addresses FROM customer LEFT JOIN (SELECT array_to_json(array_agg(json_build_object('id',address.id,'street_name',address.street_name,'street_number',address.street_number,'zip_code',address.zip_code,'city',address.city))) AS addresses,address.customer_id AS customer_id FROM customer_address AS address GROUP BY address.customer_id) addresses ON addresses.customer_id = customer.id JOIN customer_address ON customer_address.id = customer.id WHERE customer_address.street_name LIKE 'Ro%' 

\nid |  email |  first_name |  last_name |  addresses                                                                                                                                                                                        \n-: |  :------------ |  :--------- |  :-------- |  :----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- \n 1 |  john@test.com |  John |  Doe |  [{"id" : 1, "street_name" : "Route", "street_number" : "222", "zip_code" : "9000", "city" : "NY"},{"id" : 2, "street_name" : "Ro", "street_number" : "444", "zip_code" : "9000", "city" : "LA"}] \n

dbfiddle here