子查询返回1行以上MySQL错误

Question

I am trying to get three columns of data. Date, Last Years Rev, This Years Rev.

Here is what I have, but I get an error: "Subquery returns more than 1 row"

However the goal is to have more than 1 row.

SELECT 
    DATE_FORMAT(`date`, "%Y%m%d") AS `Date`,
    (SELECT `amount` AS `Revenue($)` 
        FROM `payments`
        WHERE YEAR(date) = (YEAR(CURRENT_DATE())-1)) AS `Revenue PY($)`, 
    (SELECT `amount` AS `Revenue($)`
        FROM `payments` 
        WHERE YEAR(date) = (YEAR(CURRENT_DATE()))) AS `Revenue CY($)`
FROM `payments`
GROUP BY `Date`

Sample Data:

date       | amount
2017-05-17 | 100
2017-05-17 | 200
2017-01-12 | 300
2018-05-17 | 330

Expected Outcome:

Date       | Revenue PY($) | Revenue CY($)
2017-05-17 | 300           | 0
2017-01-12 | 300           | 0
2018-05-17 | 0             | 330

Answer 1

Give this a try:

SELECT 
    DATE_FORMAT(`date`, "%Y%m%d") AS `Date`,
    `amount`,
    (SELECT SUM(`amount`) AS `Revenue($)` 
        FROM `payments`
        WHERE YEAR(date) = (YEAR(CURRENT_DATE())-1)) AS `Revenue PY($)`, 
    (SELECT SUM(`amount`) AS `Revenue($)`
        FROM `payments` 
        WHERE YEAR(date) = (YEAR(CURRENT_DATE()))) AS `Revenue CY($)`
FROM `payments`
GROUP BY `Date`

UPDATE

This should get the results as in your updated question. It gets a list of current year records and another list of previous year records, then combines them based on date. In order to combine rows from the same month/day from the two years, it adds a column sort_date which omits the year.

SELECT `date`,
    DATE_FORMAT(`date`,'%m%d') as `sort_date`,
    SUM(`Revenue CY`) as `Revenue CY`,
    SUM(`Revenue PY`) as `Revenue PY`
FROM (
    SELECT
        DATE_FORMAT(`date`,'%Y$m$d') as `date`,
        0 as `Revenue PY`,
        sum(`amount`) as `Revenue CY`,
    FROM `payments`
    WHERE YEAR(`date`) = YEAR(CURRENT_DATE())
    UNION ALL
    SELECT
        DATE_FORMAT(`date`,'%Y$m$d') as `date`,
        sum(`amount`) as `Revenue PY`,
        0 as `Revenue CY`,
    FROM `payments`
    WHERE YEAR(`date`) = YEAR(CURRENT_DATE()))
    )
GROUP BY `sort_date`
ORDER BY `sort_date`