使用'basename -s'从bash中的路径中提取文件名

Question

Can anyone explain the following code:

for var in $1\*.html
    echo $( basename -s .html $var )
done

What does -s do? Does it strip off the .html from each filename?

Answer 1

The -s suffix option means that basename removes the suffix from the filename, if present.

For example:

file=path/to/file.html
basename "$file"          => yields file.html
basename -s .html "$file" => yields file
basename -s  html "$file" => yields file.
basename -s .txt  "$file" => yields file.html since the string has no .txt extension

Not sure why you have $1\\*.html in your for loop - that suppresses the glob expansion and just yields the file that has a literal *.html in it.