[英]R match NA in a selection of columns based on the column name
I have a dataset containing per month revenue per client : Underneath is a working minimal sample.我有一个包含每个客户每月收入的数据集:下面是一个工作的最小样本。 (the real dataset runs over multiple years, all months and multple clients, but you get the picture.)
(真实的数据集运行多年,所有月份和多个客户,但您可以了解情况。)
client <-c("name1","name2","name3","name4","name5","name6")
Feb2018 <- c(10,11,NA,21,22,NA)
Jan2018 <- c(20,NA,NA,NA,58,NA)
Dec2017 <- c(30,23,33,NA,NA,NA)
Nov2017 <- c(40,22,75,NA,NA,11)
df <- data.frame(client,Feb2018,Jan2018,Dec2017,Nov2017)
My objective is to have our revenue split up between 'new','recurrent'&'lost', by adding an extra column.我的目标是通过添加一个额外的列,将我们的收入分成“新的”、“经常性的”和“丢失的”。
That is :那是 :
- new : clients having some revenue in 2018 but none in 2017. (name4 & name5)
新:客户在 2018 年有一些收入,但在 2017 年没有收入。(姓名 4 和姓名 5)
- recurrent : clients having some revenue in 2017 & 2018. (name1 & name2)
经常性:客户在 2017 年和 2018 年有一些收入。(姓名 1 和姓名 2)
- lost : clients having some revenue in 2017 but none in 2018. (name3 & name6)
流失:客户在 2017 年有一些收入,但在 2018 年没有收入。(姓名 3 和姓名 6)
I know how to use grep to select the column names,我知道如何使用 grep 来选择列名,
df[,c('client',colnames(df[grep('2018$',colnames(df))]))]
I also know how to use is.na.我也知道如何使用 is.na。 but I'm really stuck in making the combination of having a selection on both the column name & the existance of NA in the selected column.
但我真的坚持对列名和所选列中 NA 的存在进行选择的组合。
Seen I'm thinking in circles now for some hours now, I would appreciate some help.看到我现在正在思考几个小时,我会很感激一些帮助。 Thanks for reading.
谢谢阅读。
We can gather
into 'long' format and then apply the conditions and later do a join我们可以
gather
到“长”格式,然后应用条件,然后进行连接
library(dplyr)
library(tidyr)
df %>%
gather(key, val, -client, na.rm = TRUE) %>%
group_by(client) %>%
mutate(newcol = case_when(any(grepl('2018', key)) & all(!grepl('2017', key))~ 'new',
any(grepl('2018', key)) & any(grepl('2017', key)) ~ 'recurrent',
any(grepl('2017', key)) & all(!grepl('2018', key)) ~ 'lost')) %>%
distinct(client, newcol) %>%
right_join(df)
# A tibble: 6 x 6
# Groups: client [?]
# client newcol Feb2018 Jan2018 Dec2017 Nov2017
# <fctr> <chr> <dbl> <dbl> <dbl> <dbl>
#1 name1 recurrent 10.0 20.0 30.0 40.0
#2 name2 recurrent 11.0 NA 23.0 22.0
#3 name3 lost NA NA 33.0 75.0
#4 name4 new 21.0 NA NA NA
#5 name5 new 22.0 58.0 NA NA
#6 name6 lost NA NA NA 11.0
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