如何打印（加入）2个循环的结果

Question

I have 2 loops:

The first loop:

number = 1234567
number_string = str(number)
for ch in number_string:
    print(ch)

This will print:

1 
2 
3 
4 
5 
6 
7

I have another loop which is:

totalNum = len(str(abs(number)))
for i in range(totalNum, 0, -1):
  print("* 10^ ",int(i-1))

and I will get

* 10^  6
* 10^  5
* 10^  4
* 10^  3
* 10^  2
* 10^  1
* 10^  0

But how do I join these 2 loops to become the result like this:

1 * 10^  6
2 * 10^  5
3 * 10^  4
4 * 10^  3
5 * 10^  2
6 * 10^  1
7 * 10^  0

I am new to Python, so I couldn't figure out how to do that.

Answer 1

How does this work for you:

number = 1234567
totalNum = len(str(abs(number)))
for i in range(totalNum, 0, -1):
  print(str(number)[::-1][i-1] + " * 10^ ",int(i-1))

Output:

1 * 10^  6
2 * 10^  5
3 * 10^  4
4 * 10^  3
5 * 10^  2
6 * 10^  1
7 * 10^  0

Answer 2

Several ways to do this, mine uses enumerate() to index the string:

number = 1234567
number_string = str(number)
totalNum = len(str(abs(number)))

for j,i in enumerate(range(totalNum, 0, -1)):
  print(number_string[j], "* 10^ ", int(i-1))

Gives:

1 * 10^  6
2 * 10^  5
3 * 10^  4
4 * 10^  3
5 * 10^  2
6 * 10^  1
7 * 10^  0

enumerate() iterates through a sequence and gives a tuple of the index number ( j ) and the item ( i ).

Answer 3

One way, is to store the strings in a list first, then print them:

>>> number = 1234567
>>> totalNum = len(str(abs(number)))
>>> string1 = [x for x in str(number)]
>>> string2 = ['* 10^ {}'.format(i-1) for i in range(totalNum, 0, -1)]
>>> for s1, s2 in zip(string1, string2):
...     print(s1, s2)
...
1 * 10^ 6
2 * 10^ 5
3 * 10^ 4
4 * 10^ 3
5 * 10^ 2
6 * 10^ 1
7 * 10^ 0

Answer 4

This might help. You can use zip

number = 1234567
totalNum = len(str(abs(number)))
for v, i in zip(str(number), range(totalNum, 0, -1)):
  print(v, "* 10^ ",int(i-1))

Output:

1 * 10^  6
2 * 10^  5
3 * 10^  4
4 * 10^  3
5 * 10^  2
6 * 10^  1
7 * 10^  0