从表中提取数据，然后以降序回显

Question

I have the following table in my database click to view

I'm looking to find everyone whose user_group is "member", then put their ratings in an array and print their names in descending order based on their rating. So in the example given, it would output ted67945<br>ted67942 .

I currently have this code

function getInfo($info, $given_username) { // This is only used to get the rating of the given user
  require($_SERVER["DOCUMENT_ROOT"]."/movies/scripts/db.php");
  $result = mysqli_query($conn, "SELECT ".$info." FROM members WHERE username='$given_username'");
  while ($row = mysqli_fetch_array($result)) { // for each member
    return $row[$info];
  }
}
$result = mysqli_query($conn, "SELECT username FROM members WHERE user_group='member'") or die(mysql_error());
$ratings = Array();
while ($row = mysqli_fetch_array($result)) { // for each member
  $name = $row['username'];
  if(!empty($name)) {
    array_push($ratings, getInfo("rating", $name)); // This puts all people's ratings in group "member", into an array
  }
}
rsort($ratings);
foreach($ratings as $x) {
  echo $x . "<br>";
}

This, obviously, outputs the numbers. How would I use this to output the names based on their rating?

Answer 1

Why can't you just use ORDER BY in your SQL request?

SELECT username FROM members WHERE user_group='member' ORDER BY rating DESC;

This will sort your data by rating in descending order. See more .