从bash脚本循环遍历多个文件扩展名

Question

I need a bash script for use in the Linux terminal which should go something like:

#!/bin/bash 

for textgrid_file in ./*.TextGrid and for wav_file in ./*.wav
do 
   praat --run pitch.praat "$textgrid_file" "$wav_file" >> output.txt
done

Ie I need to iterate through pairs of files with extensions .textgrid and .wav because in my Praat script pitch.praat I have two arguments to pass. How can I implement it via bash scripting?

Answer 1

You can use an array support to iterate over first glob pattern and use 2nd file from array:

waves=(*.wav)

k=0
for textgrid_file in *.TextGrid; do
    praat --run pitch.praat "$textgrid_file" "${waves[k++]}" >> output.txt
done

Answer 2

If I understand you right, both filename share the same basename.

#!/bin/bash 
for textgrid_file in ./*.TextGrid 
do 
    name=$(basename $textgrid_file .TextGrid)
    wfile="$name.wav"
    praat --run pitch.praat "$textgrid_file" "$wfile" >> output.txt
done

Extract the common basename with basename.