[英]Calculation in Sum Field in SQL
I have a query which is returning me a sum group by mode of payment 我有一个查询,该查询按付款方式向我返回一笔总和
select
RTRIM(shopNo) as Shop_Number,
REPLACE(CONVERT(VARCHAR(10), DateTransaction, 103), '/', '') AS Todays_Date,
CodeModeDePaiement as Mode_Of_Payment,
SUM(convert(DOUBLE PRECISION, Amount * 100 ) * 10) As Amount
from InvoiceSettlement
where CodeModeDePaiement in
(101,130,132,135,104,103,124,107,
136,117,131,410,106,122,109,102,105,112,133,999)
and DateTransaction = '2017/12/31'
group by ShopNo,DateTransaction,CodeModeDePaiement
The output result is a below : 输出结果如下:
Shop_Number Todays_Date Mode_Of_Payment Amount
2 31122017 102 18421610
2 31122017 130 2332371390
2 31122017 132 1082810
2 31122017 106 66457640
2 31122017 117 23925000
2 31122017 133 5700000
2 31122017 999 -490653940
2 31122017 101 2404194870
I want the result to always display Sum Amount for Mode_of_Payment(101 + 999) as 101. I need the result as below : 我希望结果始终显示Mode_of_Payment(101 + 999)的总金额为101。我需要以下结果:
Shop_Number Todays_Date Mode_Of_Payment Amount
2 31122017 102 18421610
2 31122017 130 2332371390
2 31122017 132 1082810
2 31122017 106 66457640
2 31122017 117 23925000
2 31122017 133 5700000
2 31122017 101 1913540930
Use a CASE
expression to map 101 and 999 to the same thing: 使用
CASE
表达式将101和999映射到同一事物:
SELECT
RTRIM(shopNo) AS Shop_Number,
REPLACE(CONVERT(VARCHAR(10), DateTransaction, 103), '/', '') AS Todays_Date,
CASE WHEN CodeModeDePaiement IN (101, 999)
THEN 101
ELSE CodeModeDePaiement END as Mode_Of_Payment,
SUM(CONVERT(DOUBLE PRECISION, Amount * 100 ) * 10) AS Amount
FROM InvoiceSettlement
WHERE CodeModeDePaiement IN (101, 130, 132, 135, 104, 103, 124, 107, 136, 117,
131, 410, 106, 122, 109, 102, 105, 112, 133, 999) AND
DateTransaction = '2017/12/31'
GROUP BY
ShopNo,
DateTransaction,
CASE WHEN CodeModeDePaiement IN (101, 999)
THEN 101
ELSE CodeModeDePaiement END;
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