Python：从元组列表中过滤和打印元组

Question

I have a list of tuples like this:

lst = [(4, hen), (9, duck2), (45, soup), (87, Henry5)....]

Now I want only the tuples which don't have any numbers in the first index element of the tuple. So my output from the above code should be like this:

matr = [(4, hen),(45, soup)]

And I need to save the matr into a xls file. I'm able to achieve this and print it to my console, but when I save the output, I get a few blank rows embedded in between the actual rows. Please help!

Here's my code:

    # Code generating some words into the list 'words'
    d = {}
    for w in words:
        if w in d:
            d[w] += 1
        else:
            d[w] = 1

    lst = [(d[w],w) for w in d]
    lst.sort(reverse=True)

    matr = {i for i in lst if not any(c.isdigit() for c in i[1])}

    workbook = xlwt.Workbook()
    sheet = workbook.add_sheet('test')

    sheet.write(0,0,'Index')
    sheet.write(0,1,"Word")
    sheet.write(0,2,"Count")       

    i = 1
    for count, word in matr:
        if count >1:
            print count, word.encode("utf-8")
            sheet.write(i, 0, i)
            sheet.write(i, 1, word)
            sheet.write(i, 2, count)
        i += 1    


    workbook.save(r'Dummy_4.xls')

This is my output on console:

471 mistborn
2 nap
12 glare
2 diarrhea
14 wiping

But my xls output looks something like this:

Output with blank rows amidst actual rows

I'm assuming the blank rows are coming in place of the removed tuples. How to get an output without those blank rows? Please help!

Answer 1

This could be for lines with count == 1

This should fix it:

i = 1
for count, word in matr:
    if count >1:
        print count, word.encode("utf-8")
        sheet.write(i, 0, i)
        sheet.write(i, 1, word)
        sheet.write(i, 2, count)
        i += 1