[英]PHP Slim decoding JWT token
I am new to PHP and developing restful services using jwt authorization token. 我是PHP的新手,正在使用jwt授权令牌开发宁静的服务。 I have followed this GitHub example and have understood code to some extent but I am stuck on error on this line $stmt->bindParam("user_id", $decoded->context->user->user_id);
我已经遵循了这个GitHub示例,并且在一定程度上理解了代码,但是我在此行上$stmt->bindParam("user_id", $decoded->context->user->user_id);
了错误: $stmt->bindParam("user_id", $decoded->context->user->user_id);
saying 说
Notice: Array to string conversion in C:\\xampp\\htdocs\\slim2\\src\\routes.php on line. 注意:在线将C:\\ xampp \\ htdocs \\ slim2 \\ src \\ routes.php中的数组转换为字符串。
please help me solving this problem, I cant understand what is context->user->user_id where these are coming from. 请帮助我解决这个问题,我无法理解它们的来源是context-> user-> user_id。 The full code is given below 完整的代码如下
// The route to get a secured data.
$app->get('/restricted', function (Request $request, Response $response) {
$jwt = $request->getHeaders();
$key = "testsecretekey";
try {
$decoded = JWT::decode($jwt['HTTP_AUTHORIZATION'][0], $key, array('HS256'));
} catch (UnexpectedValueException $e) {
echo $e->getMessage();
}
if (isset($decoded)) {
$sql = "SELECT * FROM tokens WHERE user_id = :user_id";
try {
$db = $this->db;
$stmt = $db->prepare($sql);
$stmt->bindParam("user_id", $decoded->context->user->user_id);
$stmt->execute();
$user_from_db = $stmt->fetchObject();
$db = null;
if (isset($user_from_db->user_id)) {
echo json_encode([
"response" => "This is your secure resource !"
]);
}
} catch (PDOException $e) {
echo '{"error":{"text":' . $e->getMessage() . '}}';
}
}
});
You only have to send the token to JWT:decode. 您只需将令牌发送到JWT:decode。 Change your code to: 将您的代码更改为:
$jwt = str_replace('Bearer ', '', $jwt['HTTP_AUTHORIZATION'][0]);
$decoded = JWT::decode($jwt, $key, ['HS256']);
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