[英]Why can't I access local class outside declaring method?
I recently bumped into a rare -- but perfectly legal syntax: Local Classes . 最近,我碰到了一种罕见但合法的语法: Local Classes 。
I was wondering why can't I access a local class outside that method? 我想知道为什么我不能在该方法之外访问本地类? With what is it different from an inner class which can be access in the outer class or with an enclosed object (
outer.new Inner()
)? 它与可以在外部类中访问或使用封闭对象(
outer.new Inner()
)的内部类有什么不同?
Example: this is perfectly valid, 例子:这是完全正确的,
//this is valid
public class Outer {
int outer_x = 100;
public void test() {
Inner inner = new Inner();
inner.display();
}
public class Inner {
public void display() {
System.out.println("Outer x is: " + outer_x);
}
}
}
This is valid as well 这也是有效的
//this is valid as well
public class Outer {
int outer_x = 100;
public void test() {
Inner inner = new Inner();
inner.display();
}
public class Inner {
public void display() {
System.out.println("Outer x is: " + outer_x);
}
}
public void test2() {
Inner inner2 = new Inner();
inner2.display();
}
}
But this will not compile: 但这不会编译:
public class Outer {
int outer_x = 100;
public void test() {
class Inner {
public void display() {
System.out.println("Outer x is: " + outer_x);
}
}
Inner inner = new Inner();
inner.display();
}
public void test2() {
Inner inner2 = new Inner(); // error here
inner2.display();
}
}
Why is this so? 为什么会这样呢?
Because every call to test()
creates a complete new version of the class. 因为每次调用
test()
都会创建该类的完整新版本。 Therefore it may access (final or effectively final) local variables! 因此,它可以访问(最终或有效地最终)局部变量!
Here's a rundown what's going on. 这是一个失败的过程。
public class Outer {
public void test(int i) {
class Inner {
private int x = i; // i may be different on each call of test
public void display() {
System.out.println("Inner x is: " + x);
}
}
Inner inner = new Inner();
inner.display();
}
public void test2() {
test(1); // prints 1
test(2); // prints 2
//now imagine this is valid
Inner inner2 = new Inner();
inner2.display();// what's the value of x??
}
}
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